AP MCQ 08ABCDEFGHIJ PART 1 Question 01: What is the pH of a 0.001 M solution of a strong, monoprotic acid? 1 3 11 The Ka value is needed Question 02: When making a buffer of pH = 5, acids with the following Ka values are available. Which would be the best acid to use? 9.0 x 10-4 9.0 x 10-5 9.0 x 10-6 9.0 x 10-10 Question 03: For a buffer with a pH = 4.87, that contains a weak acid that has an equilibrium constant Ka = 1.0 x 10-5, what can be said of the ratio of [salt]:[acid]? It must favor the acid It must favor the salt The acid and salt are in a 1:1 ratio to create the 'perfect' buffer The pH is not dependent on the salt:acid ratio so it does not matter Question 04: 1.0 L of a buffer solution with a pH value = 5.92, that contains a weak acid with a pKa of 5.12 is diluted by adding water to make the new total volume 2.0 L. What is the new pH of the buffer solution? 5.12 5.92 2.00 1.00 Question 05: During the titration of a weak acid with a strong base, it is found that 22.0 mL of base is required for complete neutralization of the acid. When the titration is repeated, what can be said when the volume of base added is 11.0 mL? The pH of the solution in the flask equals the pKa of the weak acid There is more salt (conjugate base) than acid in the solution in the flask The acid has been completely neutralized The equivalence point has been reached Question 06: Which of the following salts will produce an acidic solution? Sodium ethanoate Potassium chloride Ammonium chloride Sodium nitrate Question 07: How many liters of water must be added to 1.00 liter of a strong monoprotic acid to raise the pH by 1.00 unit? 0.1 0.9 1.0 9.0 Question 08: When equal volumes of the following solutions are mixed, which results in a buffer solution? 0.01 M HNO3 & 0.01 M NH3 0.02 M HNO3 & 0.01 M NH3 0.005 M HNO3 & 0.01 M NH3 0.01 M HNO3 & 0.01 M NaOH Question 09: In order to make a buffer with a pH of 7.40, which of the following acids would be most effective, and what would be the corresponding conjugate base? H3PO4, pKa = 2.15 H2PO4-, pKa = 7.20 HPO42-, pKa = 12.3 H3PO4 & H2PO4- H2PO4- & HPO42- H2PO42- & PO43- H3PO4 & PO43- Δ