AP MCQ 07ABCDEFGHIJKLMN PART 2

  • Question 01:

    Addition of an inert gas such as neon, to an equilibrium mixture of nitrogen, hydrogen and ammonia (shown below), will result in what change?

    N2 + 3H2 ⇌ 2NH3


  • Question 02:

    Which of the following changes will result in more CO(g) being created in the equilibrium mixture?

    H2(g) + CO2(g) ⇌ H2O(g) + CO(g)


  • Question 03:

    In which of the following equilibrium systems will the mole fraction of products be increased, by the decreasing the total pressure on the system?


  • Question 04:

    Dichromate(VI) ions (orange) can be converted to chromate(VI) ions (yellow) by adding water. The equilibrium below can be established. Which of the following is initially UNCHANGED by the addition of hydroxide ions to the equilibrium mixture?

    Cr2O72-(aq) + H2O(l) ⇌ 2CrO42-(aq) + 2H+(aq)


  • Questions 05-06:

    In the equilibrium shown below, Fe3+ is a yellow brown color, and the [FeSCN]2+ ion is blood red.

    Fe3+ + SCN- ⇌ [FeSCN]2+ ∆H = negative

    Question 05:

    If a reaction mixture is plunged into an ice-bath, what observation might one reasonably expect to make?

  • Question 06:

    Addition of hydroxide ions to the system will result in what, observable change?


  • Question 07:

    Consider the equilibrium shown below.

    3Cl2(g) + 6OH-(aq) ⇌ 5Cl-(aq) + ClO3-(aq) + 3H2O(l)

    Assuming silver hydroxide to be soluble, addition of which of the following to the equilibrium mixture, will cause the equilibrium to shift to the product side?


  • Question 08:

    Which of the following equilibrium mixtures is unaffected by a change in the volume of the reaction vessel?


  • Question 09:

    Which change in conditions will cause the concentration of products in the equilibrium mixture below, to be increased?

    N2(g) + 3H2(g) ⇌ 2NH3(g) ΔH = -92 kJ mol-1


  • Question 10:

    Consider the equilibrium system shown below. The equilibrium position can be moved to the product side by applying which of the following changes?

    CO(g) + 2H2(g) ⇌ CH3OH(g)